JEE Main 2025 Matrices PYQ with solution
JEE Main 2025 Matrices PYQ with solution helps you score easy marks in JEE Main and advance. These questions are based on simple matrices formulas. Solving more question helps student to improve score in exam. Question : Let A be a 3×3 real matrix such that A2[A – 2I] – 4[A – I] = 0 ...
Read moreJEE Main 2024 Sequence and series with Solution
JEE Main 2024 Sequence and series with Solution explained here with detailed explanation. This question helps student understand Arithmetic Progression(AP), Geometric Progression(GP). Question : If loge a , loge b, loge c are in A.P. and loge a – loge 2b, loge 2b – loge 3c, loge 3c – loge a are also in A.P ...
Read moreSequence and series JEE Main 2025 PYQ Solution
Question : If the First term of an AP is 3 and the Sum of its First Four times is equal to One – fifth of the sum of the next four terms then the sum of the first 20 terms is equal to Options : (A) -1200 (B) – 1080 (C) – 1020 (D) ...
Read moreSequence and series JEE Main 2024 with solution
Question : In an increasing geometric progression of positive session terms, the sum of the second and sixth terms is 703\frac{70}{3} and the product of the third and fifth terms is 49 Then the sum of the 4th, 6th and 8th terms is Options : (A) 96 (B) 78 (C) 91 (D) 84 Sequence and ...
Read moreArithmetic Progressions JEE Main 2025 with solution
Question : Let a1, a2 …………….. a2024 be an Arithmetic Progressions Such that a1 + ( a5 + a10 + a15 +………….. + a2020 ) + a2024 = 2233 Then a1 + a2 + a3 + …………….+ a2024 is Arithmetic Progressions JEE Main 2025 with solution Solution : Find the sum of a1 + a2 ...
Read moreSequence and series JEE Main 2025 with solution
Question : The number of terms of an AP is even. The sum of all the odd terms is 24 the sum of all the even term is 30 and the last term exceeds the first by 212\frac{21}{2} then the number of terms which are integers in the AP Options : (A) 4 (B) 10 ...
Read moreCo – ordination Compounds JEE Main 2023 with solution
Question : The IUPAC name of K3[Co (C2O4)3] is Options : (a) Potassium trioxalatocabaltate(III) (b) Potassium tris(oxalato)cobalt (III) (c) Potassium tris(oxalato) cobaltate (III) (d) Potassium trioxalatocobalt (III) Co – ordination Compounds JEE Main 2023 with solution Answer : Steps required to find IUPAC Oxidation number of Co in K3[Co (C2O4)3] = 3(+1) + x + ...
Read moreJEE Main 2023 Co – ordination Compounds with Solution
Question : The set which does not have ambidentate ligand(s) is Options : (a) C2O42-, ethylene diamine, H2O (b) EDTA4-, NCS–, C2O42- (c) NO2–, C2O42-, EDTA4- (d) C2O42-, NO2–, NCS– JEE Main 2023 Co – ordination Compounds with Solution Answer : Correct answer : Option (a) Ambidentate ligand : Examples : In above question C2O42- ...
Read moreJEE Main Chemical Bonding 2016 PYQ with solution
Question : The group of molecules having identical shape is Options : (a) PCI5, IF5, XeO2F2 (b) BF3 , PCI3, XeO3 (c) SF4,XeF4,CCI4 (d) CIF3, XeOF2, XeF3+ JEE Main Chemical Bonding 2016 PYQ with solution Answer : Correct answer : option (d) CIF3 : The central atom : Chlorine The electronic configuration of chlorine is ...
Read moreChemical Bonding JEE Main 2021 PYQ with solution
Question : The hybridization of the atomic orbitals of nitrogen in NO2–, NO2+ and NH4+ respectively are : Options : (a) sp3, sp2, and sp (b) sp, sp2, and sp3 (c) sp3, sp and sp2 (d) sp2, sp and sp3 Chemical Bonding JEE Main 2021 PYQ with solution Answer : NO2– : The central atom ...
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