Sequence and series JEE Main 2024 with Solution
This Sequence and series JEE Main 2024 with Solution explained here with detailed explanation. This question helps student understand Arithmetic Progression(AP), Geometric Progression(GP). Question : If loge a , loge b, loge c are in A.P. and loge a – loge 2b, loge 2b – loge 3c, loge 3c – loge a are also in ...
Read moreSequence and series JEE Main 2025 PYQ with Solution
Question : If the First term of an AP is 3 and the Sum of its First Four times is equal to One – fifth of the sum of the next four terms then the sum of the first 20 terms is equal to Options : (A) -1200 (B) – 1080 (C) – 1020 (D) ...
Read moreSequence and series JEE Main 2024 with solution
Question : In an increasing geometric progression of positive session terms, the sum of the second and sixth terms is 703\frac{70}{3} and the product of the third and fifth terms is 49 Then the sum of the 4th, 6th and 8th terms is Options : (A) 96 (B) 78 (C) 91 (D) 84 Sequence and ...
Read moreSequence and series JEE Main 2025 Shift – II with solution
Question : Let a1, a2 …………….. a2024 be an Arithmetic Progressions Such that a1 + ( a5 + a10 + a15 +………….. + a2020 ) + a2024 = 2233 Then a1 + a2 + a3 + …………….+ a2024 is Sequence and series JEE Main 2025 Shift – II with solution Solution : Find the sum ...
Read moreSequence and series JEE Main 2025 with solution
Question : The number of terms of an AP is even. The sum of all the odd terms is 24 the sum of all the even term is 30 and the last term exceeds the first by 212\frac{21}{2} then the number of terms which are integers in the AP Options : (A) 4 (B) 10 ...
Read moreSequence and series JEE Main 2025 shift – I with solution
Question : Let TrT_rbe the rth term of an AP If for some m. Tm = 125\frac{1}{25}, T25 = 120\frac{1}{20} and 20∑r=125Tr\sum_{r=1}^{25}T_r = 13, then 5m∑r=m2mTr\sum_{r=m}^{2m}T_r is Options : (A) 98 (B) 126 (C) 112 (D) 142 Sequence and series JEE Main 2025 shift – I with solution Answer : Given 20∑r=125Tr\sum_{r=1}^{25}T_r = 13 20 ...
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Question : Consider two set A and B each containing three numbers in A.P Let the sum and the product of the elements of A be 36 and P respectively and the sum and the product of the elements of B be 36 and q respectively Let d and D be the common difference of ...
Read moreCo – ordination Compounds JEE Main 2023 shift – II with solution
Question : The IUPAC name of K3[Co (C2O4)3] is Options : (a) Potassium trioxalatocabaltate(III) (b) Potassium tris(oxalato)cobalt (III) (c) Potassium tris(oxalato) cobaltate (III) (d) Potassium trioxalatocobalt (III) Co – ordination Compounds JEE Main 2023 shift – II with solution Answer : Steps required to find IUPAC Oxidation number of Co in K3[Co (C2O4)3] = 3(+1) ...
Read moreSequence and series JEE Main 2025 shift – 2 with solution
Question : Let an be the nth term of an AP If Sn = a1 + a2 + a3 + ……………..+ an = 700, a6 = 7 and S7 = 7 then an is equal to Options : (a) 56 (b) 65 (c) 64 (d) 70 Sequence and series JEE Main 2025 shift – 2 ...
Read moreJEE Main 2023 Co – ordination Compounds with Solution
Question : The set which does not have ambidentate ligand(s) is Options : (a) C2O42-, ethylene diamine, H2O (b) EDTA4-, NCS–, C2O42- (c) NO2–, C2O42-, EDTA4- (d) C2O42-, NO2–, NCS– JEE Main 2023 Co – ordination Compounds with Solution Answer : Correct answer : Option (a) Ambidentate ligand : Examples : In above question C2O42- ...
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