JEE Main 2023 Co – ordination Compounds with Solution
Question : The set which does not have ambidentate ligand(s) is Options : (a) C2O42-, ethylene diamine, H2O (b) EDTA4-, NCS–, C2O42- (c) NO2–, C2O42-, EDTA4- (d) C2O42-, NO2–, NCS– JEE Main 2023 Co – ordination Compounds with Solution Answer : Correct answer : Option (a) Ambidentate ligand : Examples : In above question C2O42- ...
Read moreSequence and series JEE Main 2025 PYQ with Solution
Question : In an Arithmetic Progression , If S40 = 1030 and S12 = 57, then S30 – S10 is equal to Options : (a) 505 (b) 515 (c) 510 (d) 525 Sequence and series JEE Main 2025 PYQ with Solution Answer : Step : 1 Given, S40 = 1030 402\frac{40}{2}(2a + 39d ) = ...
Read moreJEE Main Chemical Bonding 2016 PYQ with solution
Question : The group of molecules having identical shape is Options : (a) PCI5, IF5, XeO2F2 (b) BF3 , PCI3, XeO3 (c) SF4,XeF4,CCI4 (d) CIF3, XeOF2, XeF3+ JEE Main Chemical Bonding 2016 PYQ with solution Answer : Correct answer : option (d) CIF3 : The central atom : Chlorine The electronic configuration of chlorine is ...
Read moreSequence and series JEE Main 2025 PYQ with solution
Question : The roots of the quadratic equation 3x2– px + q = 0 are 10th and 11th terms of an arithmetic progression with common difference 32\frac{3}{2} if the sum of the first 11 terms of the arithmetic progression is 88 the q – 2p is equal to Sequence and series JEE Main 2025 PYQ ...
Read moreChemical Bonding JEE Main 2021 PYQ with solution
Question : The hybridization of the atomic orbitals of nitrogen in NO2–, NO2+ and NH4+ respectively are : Options : (a) sp3, sp2, and sp (b) sp, sp2, and sp3 (c) sp3, sp and sp2 (d) sp2, sp and sp3 Chemical Bonding JEE Main 2021 PYQ with solution Answer : NO2– : The central atom ...
Read moreChemical Bonding JEE Main 2018 PYQ with solution
This Chemical Bonding JEE Main 2018 PYQ with solution helps student understand Hybridization and Molecular Geometry. Solving More PYQs helps student improve problem-solving skills. Question : Identify the pair in which the geometry of the species is T – shape and square pyramidal respectively Options : (a) ICI2– and ICI5 (b) IO3 and IO2F2– (c) ...
Read moreJEE Main 2023 Chemical Bonding PYQ with Solution
This JEE Main 2023 Chemical Bonding PYQ with Solution helps students learn hybridization and VSEPR Theory for JEE Main exam. Practicing PYQs improves problem- solving skills and helps students prepare better for the JEE Main. Question : Match List – I with List – II List – I (Molecule/ions) List – II (No. of lone ...
Read moreChemical Bonding JEE Main 2023 PYQ with Solution
Chemical Bonding JEE Main 2023 PYQ with Solution is explained here with a clear explanation. This question helps students understand Hybridization and VSEPR Theory for the JEE Main exam. Question : Match List I with List II List I List II A) XeF4 I) See-saw B) SF4 II) Square planar C) NH+4 III) Bent T- ...
Read moreChemical Bonding JEE Main 2022 PYQ with Detailed Solution
Question : Number of lone pairs of electrons in the central atom of SCl2 , O3 , ClF2 and SF6 respectively are Options : (a) 0 ,1 ,2 and 2 (b) 2, 1 , 2 and 0 (c) 1, 2, 2 and 0 (d) None of these Chemical Bonding JEE Main 2022 PYQ with Detailed ...
Read moreEasy Mnemonics for periodic table in English 2026
Introdution : Easy Mnemonics for periodic table in English 2026. Mnemonics helps the student to build more confidence in them on periodic table. It is easy to learn and remember the periodic trends, atomic number, block, electronic configuration. They are very useful for JEE Main and advance. Easy Mnemonics for periodic table in English 2026 ...
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